| Final Exam W2000 | Final Exam S2000 |
1. A 1.40 kg rock is launched from the surface of the Moon straight upwards. The rock is observed to rise to a height of 86.0 km above the surface of the Moon. The Moon’s mass is 7.349x10 22 kg and its mean radius is 1738 km.
(A) What is the rock’s downward acceleration when it reaches its maximum separation from the Moon?
Ans:{1.47 m/s 2}
(B) What is the total mechanical energy of the rock relative to infinity when it was launched?
Ans:{-3.76 MJ}
(C) With what velocity was the rock launched?
Ans:{516 m/s}
2. A 950 kg satellite in orbit about the Moon takes 11.0 hours to orbit once. The Moon’s mass is 7.349x10 22 kg and its mean radius is 1738 km. If the satellite’s orbit has an eccentricity of .380:
(A) What the average distance of the satellite from the center of the Moon, i.e., what is its semimajor axis?
Ans:{5800 km}
(B) What is the force of gravity of the Moon on the satellite when it is at closest distance to the Moon?
Ans:{361 N}
(C) What is the slowest the satellite will move in its orbit about the Moon?
Ans:{616 m/s}
3. A particle oscillates 270 times a minute with an amplitude of 61.0 cm. If the oscillations can be approximated by simple harmonic motion with an initial phase angle of +130.0 o for the
solution:
(A) what is the distance of the particle from the center of oscillation at the start?
Ans:{46.7 cm}
(B) what is the angular frequency in rad/sec of the oscillating particle?
Ans:{28.3 rad/s}
(C) what is the velocity of the particle when it 7/10 of the way through its cycle?
Ans:{16.0 m/s}
4. A 380 g mass oscillates on the end of a massless horizontal spring on a frictionless surface. The maximum kinetic energy and maximum acceleration of the mass is 4.70 J and 110 m/s 2.
(A) What is the maximum speed of the mass?
Ans:{4.97 m/s}
(B) How long does it take the mass to oscillate back and forth once?
Ans:{.284 s}
(C) What is the magnitude of the spring constant k of the spring?
Ans:{186 N/m}
3. A simple pendulum is constructed with a 450 gram bob and a cord with a length of 1.30 meters. The phase angle of the pendulum’s motion is 41.0 O for the SHM solution q( t) = q max sin(w t +f). If the maximum speed of the bob is 16.5 cm/s.