Electric Field on the Axis of Charged Ring
- This
is a very limited solution to the more general problem of finding the E-field
at any point in space near a ring with a charge Q spread uniformly around the ring.
- Along the axis (say the x-axis) the perpendicular components of the E-field due to charges spread around the ring cancel each other out. There is just as much charge on one side of the ring and the other.
- The net E-field (on the axis) is along the axis, outwards from the ring if the charge Q
is positive and towards the ring in the charge Q
is negative.
- The charge density l on the ring is just the total charge Q on the ring divided by its circumference 2p R.
- Treating
the differential charge dq as a point charge the differential electric field at a distance x
from the center of the ring (the origin) is given by
- Since
the sum of the y-components cancel out, the magnitude of the electric field is
equal to the sum of the x-components of the E-field. We can express this as an
integral over the differential arc length ds,
Note
that
x
and
r are both constant from any location on the ring to the point where we are calculating the E-field.
There two interesting limits.
- At the very center of the ring the E-fieldis zero at one would expect. The E-fiels of the charges spread around the ring cancel each other out.
- When one get very far from the ring so that x >> R, then R can be neglected in the denominator compared to x, and the loop looks like a point charge at large distances.